来诈金花嘛?Python实现的那种
《诈金花》又叫三张牌,诈金种是实现在全国广泛流传的一种民间多人纸牌游戏。比如JJ比赛中的诈金种诈金花(赢三张),具有独特的实现比牌规则。游戏过程中需要考验玩家的诈金种胆略和智慧。--《百度百科》 前几天在交流群里边,实现有个叫【^-^】的诈金种粉丝分享了一道扑克牌诈金花的题目,要求用Python实现,实现题目如下:
自己写一个程序,诈金种实现发牌、实现比大小判断输赢。诈金种
#### 游戏规则:
一付扑克牌,实现去掉大小王,诈金种每个玩家发3张牌,实现最后比大小,诈金种看谁赢。
有以下几种牌:
豹子:三张一样的牌,如3张6.
顺金:又称同花顺,即3张同样花色的顺子, 如红桃 5、6、7
顺子:又称拖拉机,花色不同,但是顺子,服务器租用如红桃5、方片6、黑桃7,组成的顺子
对子:2张牌一样
单张:单张最大的是A
这几种牌的大小顺序为, **豹子>顺金>顺子>对子>单张
**#### 需程序实现的点:一、思路针对这个问题,首先需要构造一副扑克牌,根据扑克牌的属性特征,进行不断的拆解,然后构造玩家用户,这里经常会用到字典和列表来存储信息,屡试不爽。
二、解决方案针对该问题,粉丝【^-^】给出了解决方法,直接上代码如下:
# -*- coding: utf-8 -*-
import random
puke = [] # 存储扑克牌
num_list = [2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A]
hua_list = [梅花, 红桃, 黑桃, 方块]
sort_dic = { 2: 0, 3: 1, 4: 2, 5: 3, 6: 4, 7: 5, 8: 6, 9: 7, 10: 8, J: 9, Q: 10, K: 11, A: 12,
对子: 15, 顺子: 30, 顺金: 60, 豹子: 100}
count_new_list = [] # 存储玩家分数和排序后排名
count_dic = { } # 存储玩家分数
# 准备52张扑克
for hua in hua_list:
for num in num_list:
a = hua + num
puke.append(a)
player_dic = { 玩家1: [], 玩家2: [], 玩家3: [], 玩家4: [], 玩家5: []}
# 随机给五个玩家发牌
# print(len(puke))
for key, value in player_dic.items():
for i in range(3):
plate = random.sample(puke, 3)
player_dic[key] = plate
for i in plate:
puke.remove(i)
print(player_dic)
# 获取玩家的牌型
def paixing(list1):
num = []
huase = []
for i in list1:
a = i[2:]
b = i[:2]
num.append(a)
huase.append(b)
return num, huase
# sort_dic = { 2: 0, 3: 1, 4: 2, 5: 3, 6: 4}
# 对数字的牌型进行排序
def sort(num):
new_num = []
sort_list2 = []
list1 = []
for i in num:
new_num.append(sort_dic[i])
new_num = sorted(new_num) # 排序后是[2, 4, 7]
for new in new_num:
sort_list2.append([k for k, v in sort_dic.items() if v == new])
for m in sort_list2:
for n in m:
list1.append(n)
return list1
# 对玩家的牌形统计分数
def count(num, huase):
a = 0
base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]
if num[0] == num[1] and num[1] == num[2]:
paixing = 豹子
a = base_count + sort_dic[paixing]
elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[
1] and huase[1] == huase[2]):
paixing = 顺金
a = base_count + sort_dic[paixing]
elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (
huase[0] != huase[
1] or huase[1] != huase[2]):
paixing = 顺子
a = base_count + sort_dic[paixing]
elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
num[0] == num[2] and num[1] != num[0]):
paixing = 对子
a = base_count + sort_dic[paixing]
else:
a = base_count
return a
# 对存储玩家分数的字典进行排序
def compare(count_dic):
d = list(zip(count_dic.values(), count_dic.keys()))
return sorted(d, reverse=True)
for key, value in player_dic.items():
num, huase = paixing(value)
num = sort(num)
count1 = count(num, huase)
count_dic[key] = count1
print(key + "的牌为:" + str(value))
count_new_list = compare(count_dic)
# print(count_new_list)
print(最终排名: + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][
1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名")代码看上去确实挺多的,超过了100行,需要花点时间去读,不过涉及的服务器托管知识点并不复杂,基本上有点Python基础,也可以理解。代码运行之后,可以看到效果如下:
不过后来我在读取这份代码的时候,发现中间有个地方写的着实有些冗余,稍微修改下,代码方面简洁一些,一些函数和变量命名加了一些对应的现实意义的单词,可读性强了一丢丢,代码如下:
# -*- coding: utf-8 -*-
import random
puke = [] # 存储扑克牌
num_list = [2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A]
hua_list = [梅花, 红桃, 黑桃, 方块]
sort_dic = { 2: 0, 3: 1, 4: 2, 5: 3, 6: 4, 7: 5, 8: 6, 9: 7, 10: 8, J: 9, Q: 10, K: 11, A: 12,
对子: 15, 顺子: 30, 顺金: 60, 豹子: 100}
count_new_list = [] # 存储玩家分数和排序后排名
count_dic = { } # 存储玩家分数
# 准备52张扑克
for hua in hua_list:
for num in num_list:
a = hua + num
puke.append(a)
player_dic = { 玩家1: [], 玩家2: [], 玩家3: [], 玩家4: [], 玩家5: []}
# 随机给五个玩家发牌
print(len(puke))
for key, value in player_dic.items():
for i in range(3):
plate = random.sample(puke, 3)
player_dic[key] = plate
for i in plate:
puke.remove(i)
print(player_dic)
# 获取玩家的牌型
def paixing(list1):
num = []
huase = []
for data in list1:
huase_type = data[:2]
pai_number = data[2:]
num.append(pai_number)
huase.append(huase_type)
return num, huase
# 对玩家的牌形统计分数
def get_score(num, huase):
base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]
if num[0] == num[1] and num[1] == num[2]:
paixing = 豹子
score = base_count + sort_dic[paixing]
elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[
1] and huase[1] == huase[2]):
paixing = 顺金
score = base_count + sort_dic[paixing]
elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (
huase[0] != huase[
1] or huase[1] != huase[2]):
paixing = 顺子
score = base_count + sort_dic[paixing]
elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
num[0] == num[2] and num[1] != num[0]):
paixing = 对子
score = base_count + sort_dic[paixing]
else:
score = base_count
return score
if __name__ == __main__:
for key, value in player_dic.items():
num, huase = paixing(value)
# 对数字的牌型进行排序
num = sorted(num)
score = get_score(num, huase)
count_dic[key] = score
print(key + "的牌为:" + str(value))
# 对存储玩家分数的字典进行排序
count_new_list = sorted(zip(count_dic.values(), count_dic.keys()), reverse=True)
print("最终排名:")
for i in range(len(count_new_list)):
print(count_new_list[i][1] + \t, end=)三、总结我是Python进阶者。本文实际生活中的诈金花游戏,基于Python编程,使用Python基础知识中的列表、字典、函数等,实现了在线诈金花的过程。